The volume of a right circular cone is V=π r2 h/3. Evaluate V for r=3 and h=5. (This "double substitution" is known as simultaneous substitution.)
Control-drag (or type) the expression for V.
Context Panel: Evaluate at a Point≻r=3,h=5
π r2 h/3→evaluate at point15⁢π
Expression palette: Evaluation template
π r2h/3x=a|f(x)r=3,h=5 = 15⁢π
Use the eval command.
The brackets around the substitution rules are essential.
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