CurveSketchSteps - Maple Help
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Student[Basics]

  

CurveSketchSteps

  

show steps in the plotting of a specified expression

 

Calling Sequence

Parameters

Description

Examples

Compatibility

Calling Sequence

CurveSketchSteps(ex, opts)

Parameters

ex

-

expression or string

opts

-

options of the form keyword=value where keyword is one of displaystyle, output

Description

• 

The CurveSketchSteps command is used to show how a student might plot a basic expression.

• 

This command handles linear and quadratic polynomials in one variable, as well as single trig, log, 1/x and exponentials that are shifted and scaled. It does not support combinations of these functions and works best when the input is already simplified.

• 

To avoid automatic simplifications the input expression can be given as a string. For example, calling CurveSketchSteps(cos(x-Pi/2)) will first evaluate cos(x-Pi/2) to sin(x) using normal Maple evaluation rules.  Instead, call CurveSketchSteps("cos(x-Pi/2"), to internally make use of InertForm:-Parse and avoid this simplification.

• 

The displaystyle and output options can be used to change the output format.  See OutputStepsRecord for details.

• 

This function is part of the Student:-Basics package.

Examples

withStudent:-Basics:

CurveSketchSteps2sin3x+π3+1

Let's plot2sin3x+π3+1Compared to the plot ofsinx, we have a vertical stretch by a factor of22sin3x+π9+1Then, we have a horizontal compression by a factor of132sin3x+π9+1Then, we have a vertical shift of12sin3x+π9+1Then, we have a horizontal shift ofπ92sin3x+π9+1Apply the horizontal shift and stretch to the range,x=2π..2π2π13+π9..2π13+π9=−2.443460953..1.745329252We can now plot using the information extractedPLOT...

(1)

CurveSketchSteps2x2+4x+10

Let's plot2x2+4x+102x2+4x+10Complete the square2x+12+8With the expression in vertex form we can extract valuable information2x+12+8The coefficient2of thex+12term indicates a parabola that opensupand has a verticalstretchof22x+12+8We have a horizontal shift of−1and a vertical shift of8which gives a vertex of (−1,8)2x+12+8We can now plot using the information extractedPLOT...

(2)

CurveSketchSteps4x+10,output=typeset

Let's plot4x+104x+10This is a line; find two points and draw a line through themy=4x+10Setx= 0 to solve for y intercepty=10This gives a y intercept of (0,10)y=10Set expresson to 0 to solve forxintercept0=4x+10Rearrange expression4x+10=0Subtract10from both sides4x+1010=010Simplify4x=−10Divide both sides by44x4=−104Simplifyx=52This gives anxintercept of (52,0)x=52By connecting through the two points we can plot the linePLOT...

(3)

CurveSketchSteps23x+2,output=link

https://learn.maplesoft.com/d/GSFGIHMLARGPFKFTJPNMOFENFUEHOLNUBJBIFUIMORFQFHHRFIGUJPIFNHCRJLAOERDSHUNHJOJNAODNEMNUFKOHFKLJIPCOIJCU

Compatibility

• 

The Student[Basics][CurveSketchSteps] command was introduced in Maple 2022.

• 

For more information on Maple 2022 changes, see Updates in Maple 2022.

See Also

Student:-Basics

Student:-Basics:-FactorSteps

Student:-Basics:-LinearSolveSteps

Student:-Basics:-OutputStepsRecord

Student:-Calculus1:-ShowSolution

Student:-Calculus1:-ShowSteps