Define now an arbitrary tensor
So is a 4D tensor with only one free index, where the position of the time-like component is indicated by the different sign in the signature
Accordingly, the 3+1 decomposition of is
The 3+1 decomposition of the inert representation %g_[mu,nu] of the 4D spacetime metric; use the inert representation when you do not want the actual components of the metric appearing in the output
Note the position of the component %g_[0, 0], related to the trailing position of the time-like component in the signature .
Compare the decomposition of the 4D inert with the decomposition of the 4D active spacetime metric
The 3D space part of is actually equal to minus the 3D metric (equations (84.7) and (84.9) of Landau's book [1])
To derive the formula above for the covariant components of the 3D metric, Decompose into 3+1 the identity
To the side, for illustration purposes, this is the 3 + 1 decomposition excluding the repeated indices, and excluding the free indices
Compare with a full decomposition
is a symmetric matrix of equations involving non-contracted occurrences of , and . Isolate, in , , that you input as %g_[~j, ~0], and substitute into
Collect , that you input as %g_[~j, ~i]
Since the right-hand side is the identity matrix and, from (27), , the expression between parenthesis, multiplied by -1, is the reciprocal of the contravariant 3D metric , that is the covariant 3D metric , in accordance to its definition for the signature