form = row or form = column

This option determines whether the compressed sparse column form or the compressed sparse row form is returned. The default is compressed sparse column form.

output = CB or R or X or a list of these values

If output is set to CB, then only CB is returned. Similarly for R and X. If a list of these values is selected, then Maple returns the corresponding values in that order, as an expression sequence. The default value is [CB, R, X]: return the sequence of all three Vectors.

cbbase = posint

rbase = posint

These options determines at what number Maple starts numbering the rows and columns. The default is 1, corresponding to the standard Maple convention. Other values, in particular 0, are mainly useful if the result is passed to external code.

The setting of cbbase changes the values in $\mathrm{CB}$: it changes the start of indexing into $R$ and $X$. The setting of rbase changes the values in $R$: it changes the start of indexing into $A$.

The CompressedSparseForm function computes either the compressed sparse row form or the compressed sparse column form of the input Matrix $A$, which needs to have one of the hardware data types. It thus performs the opposite function to FromCompressedSparseForm.

The compressed sparse column form of an $n$ by $m$ Matrix $A$ with $k$ nonzero entries consists of three Vectors, $\mathrm{CB}$, $R$, and $X$. These are obtained by sorting the $k$ nonzero entries of $A$ first by column, and then within each column sorting the entries by row. Now $X$ is the $k$-element Vector of these nonzero values in $A$ in this order, and $R$ is the $k$-element Vector of row indices at which these values occur. $\mathrm{CB}$ is an $n+1$-element Vector; ${\mathrm{CB}}_i$ is the index in both $X$ and $R$ where the $i$th column starts. We always have ${\mathrm{CB}}_1=1$ and ${\mathrm{CB}}_{n+1}=k+1$, so that the entries in column $i$ have indices ${\mathrm{CB}}_i$ up to, but not including, ${\mathrm{CB}}_{i+1}$. (If the $\mathrm{cbbase}$ option below is used, then ${\mathrm{CB}}_1=\mathrm{cbbase}$ and ${\mathrm{CB}}_{n+1}=k+\mathrm{cbbase}$ and a similar statement holds.)

The compressed sparse row form is very similar, but with the roles of rows and columns interchanged. Specifically, we first sort $A$ by row and then within each row by column; $X$ is still the nonzero values occurring in $A$. However, $R$ is the $k$-element Vector of column indices. Similarly, ${\mathrm{CB}}_i$ is the index in $X$ and $R$ where the $i$th row starts.

The compressed sparse forms are most useful for sparse Matrices. If $A$ does not have sparse storage (as determined by $\mathrm{rtable\_option}\left(X\,\mathrm{storage}\right)$ being either $\mathrm{sparse}$ or ${\mathrm{sparse}}_{\mathrm{upper}}$ or ${\mathrm{sparse}}_{\mathrm{lower}}$), then a sparse storage copy is made before determining the compressed sparse form.

If $A$ has any indexing functions (as determined by $\mathrm{rtable\_indfns}\left(A\right)$), then these are bypassed when determining the compressed sparse row or column form: since CompressedSparseForm is a low level command, Maple returns the compressed sparse form of the stored entries only. For example, if a Matrix is defined with option $\mathrm{shape}=\mathrm{symmetric}$ and $\mathrm{storage}={\mathrm{sparse}}_{\mathrm{upper}}$, then only one of each pair of off-diagonal entries will be represented in the compressed sparse form. However, if $A$ has indexing functions but no sparse storage, then the copy made to give it sparse storage, as explained above, typically gets rid of the indexing function and stores all nonzero entries.

The code for CompressedSparseForm relies on $A$ being a NAG-sparse Matrix (potentially after copying it to give it sparse storage); that is, its datatype as returned by rtable_options needs to be one of these values:

$\mathrm{sfloat},\mathrm{complex}\left(\mathrm{sfloat}\right),{\mathrm{integer}}_1,{\mathrm{integer}}_2,{\mathrm{integer}}_4,{\mathrm{integer}}_8,{\mathrm{float}}_4,{\mathrm{float}}_8,{\mathrm{complex}}_8$

$\mathrm{with}\left(\mathrm{LinearAlgebra}\right)\:$

$m≔\mathrm{Matrix}\left(6\,6\,\left\{\left(1\,2\right)=-81\,\left(2\,3\right)=-55\,\left(2\,4\right)=-15\,\left(3\,1\right)=-46\,\left(3\,3\right)=-17\,\left(3\,4\right)=99\,\left(3\,5\right)=-61\,\left(4\,2\right)=18\,\left(4\,5\right)=-78\,\left(5\,6\right)=22\right\}\,\mathrm{datatype}=\mathrm{integer}\left[4\right]\right)$

$m≔\left[\begin{array}{cccccc}0& \mathrm{-81}& 0& 0& 0& 0\\ 0& 0& \mathrm{-55}& \mathrm{-15}& 0& 0\\ \mathrm{-46}& 0& \mathrm{-17}& 99& \mathrm{-61}& 0\\ 0& 18& 0& 0& \mathrm{-78}& 0\\ 0& 0& 0& 0& 0& 22\\ 0& 0& 0& 0& 0& 0\end{array}\right]$

$\mathrm{CompressedSparseForm}\left(m\right)$

$\left[\begin{array}{c}1\\ 2\\ 4\\ 6\\ 8\\ 10\\ 11\end{array}\right],\left[\begin{array}{c}3\\ 1\\ 4\\ 2\\ 3\\ 2\\ 3\\ 3\\ 4\\ 5\end{array}\right],\left[\begin{array}{c}\mathrm{-46}\\ \mathrm{-81}\\ 18\\ \mathrm{-55}\\ \mathrm{-17}\\ \mathrm{-15}\\ 99\\ \mathrm{-61}\\ \mathrm{-78}\\ 22\end{array}\right]$

$\mathrm{CompressedSparseForm}\left(m\,'\mathrm{form}=\mathrm{row}'\right)$

$\left[\begin{array}{c}1\\ 2\\ 4\\ 8\\ 10\\ 11\\ 11\end{array}\right],\left[\begin{array}{c}2\\ 3\\ 4\\ 1\\ 3\\ 4\\ 5\\ 2\\ 5\\ 6\end{array}\right],\left[\begin{array}{c}\mathrm{-81}\\ \mathrm{-55}\\ \mathrm{-15}\\ \mathrm{-46}\\ \mathrm{-17}\\ 99\\ \mathrm{-61}\\ 18\\ \mathrm{-78}\\ 22\end{array}\right]$

$\mathrm{CompressedSparseForm}\left(m\,'\mathrm{cbbase}'=0\right)$

$\left[\begin{array}{c}0\\ 1\\ 3\\ 5\\ 7\\ 9\\ 10\end{array}\right],\left[\begin{array}{c}3\\ 1\\ 4\\ 2\\ 3\\ 2\\ 3\\ 3\\ 4\\ 5\end{array}\right],\left[\begin{array}{c}\mathrm{-46}\\ \mathrm{-81}\\ 18\\ \mathrm{-55}\\ \mathrm{-17}\\ \mathrm{-15}\\ 99\\ \mathrm{-61}\\ \mathrm{-78}\\ 22\end{array}\right]$

$\mathrm{CompressedSparseForm}\left(m\,'\mathrm{rbase}'=0\right)$

$\left[\begin{array}{c}1\\ 2\\ 4\\ 6\\ 8\\ 10\\ 11\end{array}\right],\left[\begin{array}{c}2\\ 0\\ 3\\ 1\\ 2\\ 1\\ 2\\ 2\\ 3\\ 4\end{array}\right],\left[\begin{array}{c}\mathrm{-46}\\ \mathrm{-81}\\ 18\\ \mathrm{-55}\\ \mathrm{-17}\\ \mathrm{-15}\\ 99\\ \mathrm{-61}\\ \mathrm{-78}\\ 22\end{array}\right]$

$\mathrm{m2}≔\mathrm{Matrix}\left(\left[\left[0\,1\,0\right]\,\left[2\,0\,0\right]\,\left[3\,0\,4\right]\,\left[5\,6\,7\right]\right]\,'\mathrm{datatype}=\mathrm{float}'\right)$

$\mathrm{m2}≔\left[\begin{array}{ccc}0.& 1.& 0.\\ 2.& 0.& 0.\\ 3.& 0.& 4.\\ 5.& 6.& 7.\end{array}\right]$

$\mathrm{cb},r,x≔\mathrm{CompressedSparseForm}\left(\mathrm{m2}\right)$

$\mathrm{cb},r,x≔\left[\begin{array}{c}1\\ 4\\ 6\\ 8\end{array}\right],\left[\begin{array}{c}2\\ 3\\ 4\\ 1\\ 4\\ 3\\ 4\end{array}\right],\left[\begin{array}{c}2.\\ 3.\\ 5.\\ 1.\\ 6.\\ 4.\\ 7.\end{array}\right]$

$\mathrm{column}≔2$

$\mathrm{column}≔2$

$r\left[\mathrm{cb}\left[\mathrm{column}\right]..\mathrm{cb}\left[\mathrm{column}+1\right]-1\right]$

$\left[\begin{array}{c}1\\ 4\end{array}\right]$

$x\left[\mathrm{cb}\left[\mathrm{column}\right]..\mathrm{cb}\left[\mathrm{column}+1\right]-1\right]$

$\left[\begin{array}{c}1.\\ 6.\end{array}\right]$

$\mathrm{m3}≔\mathrm{Matrix}\left(3\,3\,\left(i\,j\right)\mapsto i-j\right)$

$\mathrm{m3}≔\left[\begin{array}{ccc}0& \mathrm{-1}& \mathrm{-2}\\ 1& 0& \mathrm{-1}\\ 2& 1& 0\end{array}\right]$

$\mathrm{CompressedSparseForm}\left(\mathrm{m3}\right)$

Error, (in LinearAlgebra:-CompressedSparseForm) cannot compute compressed sparse form of a Matrix with non-hardware datatype anything

$\mathrm{m3}≔\mathrm{Matrix}\left(\mathrm{m3}\,\mathrm{datatype}=\mathrm{integer}\left[4\right]\right)$

$\mathrm{m3}≔\left[\begin{array}{ccc}0& \mathrm{-1}& \mathrm{-2}\\ 1& 0& \mathrm{-1}\\ 2& 1& 0\end{array}\right]$

$\mathrm{cb},r,x≔\mathrm{CompressedSparseForm}\left(\mathrm{m3}\right)$

$\mathrm{cb},r,x≔\left[\begin{array}{c}1\\ 3\\ 5\\ 7\end{array}\right],\left[\begin{array}{c}2\\ 3\\ 1\\ 3\\ 1\\ 2\end{array}\right],\left[\begin{array}{c}1\\ 2\\ \mathrm{-1}\\ 1\\ \mathrm{-2}\\ \mathrm{-1}\end{array}\right]$

$\mathrm{m4}≔\mathrm{Matrix}\left(6\,\mathrm{datatype}=\mathrm{integer}\left[4\right]\,\mathrm{shape}=\mathrm{antisymmetric}\,\mathrm{storage}=\mathrm{sparse}\left[\mathrm{lower}\right]\,\left(i\,j\right)\mapsto \mathrm{`if`}\left(\mathrm{irem}\left(i+j\,2\right)=1\,i-j\,0\right)\right)$

$\mathrm{m4}≔\left[\begin{array}{cccccc}0& \mathrm{-1}& 0& \mathrm{-3}& 0& \mathrm{-5}\\ 1& 0& \mathrm{-1}& 0& \mathrm{-3}& 0\\ 0& 1& 0& \mathrm{-1}& 0& \mathrm{-3}\\ 3& 0& 1& 0& \mathrm{-1}& 0\\ 0& 3& 0& 1& 0& \mathrm{-1}\\ 5& 0& 3& 0& 1& 0\end{array}\right]$

$\mathrm{CompressedSparseForm}\left(\mathrm{m4}\right)$

$\left[\begin{array}{c}1\\ 4\\ 6\\ 8\\ 9\\ 10\\ 10\end{array}\right],\left[\begin{array}{c}2\\ 4\\ 6\\ 3\\ 5\\ 4\\ 6\\ 5\\ 6\end{array}\right],\left[\begin{array}{c}1\\ 3\\ 5\\ 1\\ 3\\ 1\\ 3\\ 1\\ 1\end{array}\right]$

The LinearAlgebra[CompressedSparseForm] command was introduced in Maple 17.

For more information on Maple 17 changes, see Updates in Maple 17.