The convert/ln function converts all inverse trigonometric functions appearing in the expression to their corresponding logarithmic form.

$\mathrm{convert}\left(\arcsin \left(x\right)\,\ln \right)$

$\mathrm{-I}\ln \left(\sqrt{-x^2+1}+\mathrm{I}x\right)$

$\mathrm{convert}\left(\mathrm{arctanh}\left(x\right)\,\ln \right)$

$\frac{\ln \left(x+1\right)}{2}-\frac{\ln \left(1-x\right)}{2}$