The procedure isolate attempts to isolate the second argument expr in the first argument eqn and solves eqn for expr.

If eqn is an equation (=) or inequation (<>) then isolate attempts to put expr on the left-hand side. If eqn is an inequality then isolate may put expr on the right- or left-hand side whichever isolates expr more completely.

If the first argument is not a relation, then the equation $\mathrm{eqn}=0$ is assumed.

The optional third argument iter controls the maximum number of transformation steps that isolate performs.  The default is 100000.

For direct solutions of equations, solve may be more efficient than isolate, which is intended, primarily, for use in an interactive Maple session.

Furthermore, whereas isolate returns an equation equivalent to its input, solve returns solutions to its input equations, and can handle systems of equations with multiple solutions.

$\mathrm{isolate}\left(4x\sin \left(x\right)=3\&comma;\sin \left(x\right)\right)$

$\sin \left(x\right)=\frac{3}{4x}$

$\mathrm{isolate}\left(2x+1\le 6\&comma;x\right)$

$x\le \frac{5}{2}$

$\mathrm{isolate}\left(-2x+1\le 0\&comma;x\right)$

$\frac{1}{2}\le x$

$\mathrm{isolate}\left(x^2-3x-5\&comma;x^2\right)$

$x^2=3x+5$

$\mathrm{isolate}\left(x^2-3x-5\&comma;x\&comma;0\right)$

$x^2-3x-5=0$

$\mathrm{isolate}\left(x^2-3x-5\&comma;x\&comma;1\right)$

$x^2-3x=5$

$\mathrm{isolate}\left(x^2-3x-5\&comma;x\&comma;2\right)$

$x=\frac{3}{2}-\frac{\sqrt{29}}{2}$

$\mathrm{isolate}\left(x^2-3x-5\&comma;x\right)$

$x=\frac{3}{2}-\frac{\sqrt{29}}{2}$

$\mathrm{solve}\left(x^2-3x-5\&comma;x\right)$

$\frac{3}{2}+\frac{\sqrt{29}}{2},\frac{3}{2}-\frac{\sqrt{29}}{2}$

$p\mathrm{diff}\left(h\left(x\right)\&comma;x\right)+w+\mathrm{int}\left(h\left(x\right)\&comma;x\right)=s\left(x\right)$

$p\left(\frac{\&DifferentialD;}{\&DifferentialD;x}h\left(x\right)\right)+w+\int h\left(x\right)\&DifferentialD;x=s\left(x\right)$

$\mathrm{isolate}\left(\&comma;h\left(x\right)\right)$

$p\left(\frac{\&DifferentialD;}{\&DifferentialD;x}h\left(x\right)\right)+\int h\left(x\right)\&DifferentialD;x=s\left(x\right)-w$