From the partial-fraction decomposition in Example 6.4.2, it follows that

Note once again that Maple integrates $1\/x$ to $\ln \left(x\right)$, not $\ln \(\left|x\right|\)$, relying on a complex constant of integration to counterbalance the logarithm of a negative number.

Table 6.5.1(a) shows the result of invoking the Partial Fractions rule in the  tutor when the Sum and Constant Multiple rules are taken as Understood Rules. The next step the tutor insists on is the change of variables $u\=x-4$, the outcome of which is the term $5 \ln \left(x-4\right)$; similarly for the integration of the other partial fraction.